If Alan is taking first turn then he can win definetely.
He has to put first coin exactly at center. After that just put coin exactly diameterically opposite (e.g. on a diameter passing through center of Brayn's coin but to opposite side and with same distance from center). Since table is circular and so are coins is gauranteed that whenever Brayn put a coin there will be a space available on diameterically opposite side due to symmetry.
So, as long as Brayn can put a coin Alan can also put one. Hence, this way Alan will put the last coin if follows above strategy.
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