Walter Effross <eff...@wcl.american.edu>: Oct 09 11:21AM I'm still getting the messages. Several times, I've tried to unsubscribe by sending an e-mail to the address listed for that; each time, I get back a message saying that it's invalid because I'm not a member. Best regards, Walter ________________________________ From: 'David Ash' via Competition Corner Participant Discussion <competition-corner-p...@googlegroups.com> Sent: Friday, October 8, 2021 10:53 PM To: Competition Corner Participant Discussion <competition-corner-p...@googlegroups.com> Subject: Re: finite field problem It might be good if Walter verified this--or at least if he verifies if it did not work since he wouldn't see this if it did! I'm still seeing the total number of members as 116 which is the number it has been for a little while now. Also if you click on 'My membership settings' you can adjust the amount of email you get from GG. If someone wants to occasionally check in on how this discussion is going but wants to minimize spam, they can adjust the settings to get less or no email when people make postings. On Friday, October 8, 2021 at 6:23:26 PM UTC-7 igl...@gmail.com wrote: I do think it worked. You are not in the member list any more. On Friday, October 8, 2021 at 4:38:00 PM UTC-5 Walter Effross wrote: Could someone please unsubscribe me? I've tried the instructions at the bottom of these e-mails, but I'm still in the loop. I'm still happy to talk about the project, going forward. Thank you! Walter ________________________________ From: 'David Ash' via Competition Corner Participant Discussion <competition-corner-p...@googlegroups.com> Sent: Friday, October 8, 2021 5:29 PM To: Competition Corner Participant Discussion <competition-corner-p...@googlegroups.com> Subject: Re: finite field problem There are, I believe, many possibilities for p(x) that will work, but some are easier to prove than others. Yes, x^10+x^3+1 is irreducible over GF(2) and proving that is one important step. It does then follow that 1, x, x^2, ..., x^9 form a basis but unfortunately this basis is not in the form that we are asked to find a basis. If p(x)=x^7 works, we'd have to somehow prove that x^7, x^14, x^28, x^56, ..., x^3584 form a basis. I'm not sure that you've proved that. It may very well be true--I haven't worked out the details but do know that there are a significant number of polynomials p(x) that work--there is not just one unique solution. However I believe there may be other polynomials p(x) which work and which require much less rote arithmetic (computation) to prove. On Friday, October 8, 2021 at 1:33:11 PM UTC-7 t...@bellefleurbooks.com wrote: Dear David: My inclination was wrong. Step 1 was a waste of effort. When you skip step 1, step 2 amounts to computing p(x) assuming that 1, x, x^2, . . . , x^9 form a basis. There are multiple possibilities for p here, the simplest being p(x) = x^7. Nevertheless, you still have to prove that 1, x, x^2, . . . , x^9 form a basis (step 3) which is equivalent to proving that x^10+x^3+1 cannot be factored. You have much the same issue (step 3) in your approach. You state that x^9+x^7+x^6+x^3+1 is not 1, but it could be equal to 1 if x^9+x^7+x^6+x^3 = 0, i.e., if the two polynomials, x^9+x^7+x^6+x^3 and x^10+x^3+1 shared a common factor. In fact, they do not, but you have to prove as much. Proving that x^10+x^3+1 cannot be factored, or something like this, is something to look for in the proofs submitted. It is a good problem. Sincerely, Tom On 2021-10-08 12:28, 'David Ash' via Competition Corner Participant Discussion wrote: -- You received this message because you are subscribed to the Google Groups "Competition Corner Participant Discussion" group. To unsubscribe from this group and stop receiving emails from it, send an email to competition-corner-partici...@googlegroups.com. 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Istvan Lauko <igl...@gmail.com>: Oct 09 10:02AM -0700 I did communicate with Walter. He is still a member, but now he does not receive any emails. I wander, if we should do this as a default for all, who are not active here (would hate to generate unwanted emails for anyone). Unfortunately there is no option for weekly or monthly "digest", only daily. On Saturday, October 9, 2021 at 6:21:16 AM UTC-5 Walter Effross wrote: |
Istvan Lauko <igl...@gmail.com>: Oct 09 10:05AM -0700 I mean I wonder.... (a case in point) On Saturday, October 9, 2021 at 12:02:01 PM UTC-5 Istvan Lauko wrote: |
t...@bellefleurbooks.com: Oct 09 05:02PM -0500 Dear David: I proved that p(x) can equal x^7, but I did not provide the proof. You know how to do it. By the way, every solution, p(x), has an x^7 term. I can prove this too but have not provided the proof. The original problem is a good problem--a little more challenging than the Sierpinski tower. Sincerely, Tom On 2021-10-08 16:29, 'David Ash' via Competition Corner Participant Discussion wrote: |
David Ash <david_...@yahoo.com>: Oct 09 04:31PM -0700 Tom, Yes--it appears to be true that every solution must have a (nonzero) x^7 term. To see this, first observe that it is fairly easy to show that for any element t in GF(2^10), t^1024=t. So if we repeatedly square any element of the field, we eventually get back to the original element. Note that the basis we are asked to construct basically involves taking an element and then squaring it nine times in succession to produce the other nine elements of the basis. Next we look at the squares of each of 1, x, x^2, ..., x^9: square of 1 is 1 square of x is x^2 square of x^2 is x^4 square of x^3 is x^6 square of x^4 is x^8 square of x^5 is x^3+1 square of x^6 is x^5+x^2 square of x^7 is x^7+x^4 square of x^8 is x^9+x^6 square of x^9 is x^8+x^4+x Note that the operation of squaring never introduces an x^7 term unless we already have an x^7 term to start with. Since a basis, by definition, must span the entire space, the only way a basis generated by squaring can span x^7 terms is if the initial element includes an x^7 term. This might be a good alternative problem to the original problem BTW--instead of asking people to give an example of a p(x) that works instead ask them to prove that p(x) must include an x^7 term. On Saturday, October 9, 2021 at 3:02:37 PM UTC-7 t...@bellefleurbooks.com wrote: |
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