wij <
wyni...@gmail.com> writes:
> What are those numbers near either sides of 1?
> 0.999... and 1.000..1 do not exist?
0.999... exists (it's another way to write 1) and infinitely many
numbers of the form 1.000...1 exist.
> Because every number approaching 1 is 1?
No number approaches 1. Sequences (and/or functions) can approach 1.
0.999... denotes a limit whose value is 1. 1.000...1 denotes a set of
numbers all slightly greater than 1.
You need a new notation. You can define 0.999___ in any way you like,
and I think you intended the ... in 1.000...1 so suggest an infinite
sequence of zero digits so you might be better off writing that as
1.(000___)1.
> So, all numbers very close to π is π?
No. Only numbers equal to n are equal to n.
> (sin(x+h)-sin(x))/h is very close to cos(x), thus, is EQUAL to
> cos(x).
No.
> A[0]=0
> A[n]=(A[n-1]+1)/2
> What is A[n] when n approaches infinity? Oh! 'when' is invalid!
> 'infinity' is a concept, not a number!
No, 'when' is fine and infinity is a concept. Why do you worry that
it's a concept? You can make it a number by stating that you are using
a number system that includes infinity.
> But, A[∞] will? get to 1, ℝ is dense, density property is not
> broken.
A[∞] is not (usually) defined, even in number systems that include
infinity because, in the usual models, ∞ - 1 = ∞.
> A transcendental number is a number that is not algebraic, not the kind of
> number +-*/ can yield.
No, they can't be got from a finite number of basic operations on
rationals.
> But ℝ is closed and complete, Oh! where are all those irrational
> numbers gone?
There are there, defined as they always have been. R is closed under
the operation of taking least upper bounds (or taking limits, or
Dedekind cuts or...). This is all basic stuff.
--
Ben.