Algorithm Numbering Conflict with algorithmic and algorithm2e

[AikidoGuy]

Does anyone know how to change the following example so that the
second algorithm will be numbered with a 2? i.e. "Algorithm 2" instead
of "Algorithm 1".

Thank you,
Alan

\documentclass{article}
%
% For algorithms (1)
%
% http://gicl.cs.drexel.edu/people/tjkopena/wiki/index.php?n=SWAT.Algorithm2eTooManyBrackets
\makeatletter
\newif\if@restonecol
\makeatother
\let\algorithm\relax
\let\endalgorithm\relax
\usepackage[algo2e,ruled,vlined]{algorithm2e} % need for algorithm
environment (name is algorithm2e because of algo2e option)
%
% For algorithms (2)
\usepackage{algorithm}
\usepackage{algorithmic}
\renewcommand{\algorithmiccomment}[1]{\hfill $\rhd$ \textsf{\textit
{#1}}}
%
\begin{document}
%
% First Algorithm
\begin{algorithm}
\caption{My First Algorithm}
\label{algorithm:one} \textbf{Input:} blah
\begin{algorithmic}[1]
\STATE $k \Leftarrow 1$
\end{algorithmic}
\end{algorithm}
%
% Second Algorithm
\begin{algorithm2e}[h!]
\caption{My Second Algorithm\label{algorithm:two}}
%\dontprintsemicolon
\linesnumbered
\SetLine
Let $A \Leftarrow foo(\emptyset, \emptyset)$ \;
\end{algorithm2e}
\end{document}