Integrals on the HP-48G
David Lopez
I've been trying to evaluate the following:
the indefinite integral of: e^(2x) sin(3x) dx
Normally I would use the formula for Integartion by parts, but it
would be nice to verify my answer. When I plug in the numbers the
HP-48G just bounces back the integral. I haven't had problems trying
simple integrals like x^2. In this case it returns the right answer:
0.3333...*(x^3)
There is something else I've noticed about the HP48, If I try to raise
zero to the power of zero ( 0^0) it returns the ans: 1. Every other
calculator I have (TI-82, Casio and sharp) gives me an error message.
Have the guys at HP discovered something new?
I would truly appreciate any answers to these questions...
Davi...@ix.netcom.com
Bernard Parisse
>
>
>I've been trying to evaluate the following:
>
> the indefinite integral of: e^(2x) sin(3x) dx
>
The best way to do it is to use
\int e^(2x) sin(3x) dx = imaginary part of
\int e^( (2+3i)*x ) dx
so no integration by part! Compute the integral and use Euler formula
to go back to sin and cos.
Bernard Parisse.
Seth Arnold
davi...@ix.netcom.com (David Lopez ) wrote:
>There is something else I've noticed about the HP48, If I try to raise
>zero to the power of zero ( 0^0) it returns the ans: 1. Every other
>calculator I have (TI-82, Casio and sharp) gives me an error message.
>Have the guys at HP discovered something new?
They just feel it wasn't worth checking for zero, so give the answer that looks
right on a graph. (check the alt.math faq, or something similar for more info.)
--
Seth Arnold | hid...@agora.rdrop.com | http://www.rdrop.com/~hideki
Jesse Mikael Wolff
David Lopez <davi...@ix.netcom.com> wrote:
>
>I've been trying to evaluate the following:
>
> the indefinite integral of: e^(2x) sin(3x) dx
>
>would be nice to verify my answer. When I plug in the numbers the
>HP-48G just bounces back the integral. I haven't had problems trying
>simple integrals like x^2. In this case it returns the right answer:
>0.3333...*(x^3)
Can't answer this one, except to say that the 48 can only do simple
indefinite integrals.
>There is something else I've noticed about the HP48, If I try to raise
>zero to the power of zero ( 0^0) it returns the ans: 1. Every other
>calculator I have (TI-82, Casio and sharp) gives me an error message.
>Have the guys at HP discovered something new?
Read the FAQ, it has a lenghty discussion on this.
Adios,
--
jesse wolff wol...@cae.wisc.edu http://www.engr.wisc.edu/~wolffj
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