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matlab sintax
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baltam
Sep 5, 2012, 6:19:05 AM9/5/12
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What does this mean?
t = [0, 0, 1, 0, 1, 0, 0, 1, 0];
b=sum((t-[t(2:end),0])==-1);
t = [0, 0, 1, 0, 1, 0, 0, 1, 0];
b=sum((t-[t(2:end),0])==-1);
dpb
Sep 5, 2012, 9:21:49 AM9/5/12
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(t-[t(2:end),0])
((t-[t(2:end),0])==-1)
BTW, it could be written as
b=sum([-diff(t) 0]==-1);
--
baltam
Sep 5, 2012, 10:21:07 AM9/5/12
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dpb <no...@non.net> wrote in message <k27jl0$n1v$1...@speranza.aioe.org>...
Using the Command Window I understand that is a method to count the number of (-1) in the result.
The expression t-[t(2:end),0] executes the difference among each terms of the t vector.
Considering t = [0, 0, 1, 0, 1, 0, 0, 1, 0];
the expression t-[t(2:end),0] gives as result [0 -1 1 -1 1 0 -1 1 0]
so it computes:
0-0 = 0
0-1 = -1
1-0 = 1
and so on
Why didn't I use the Command Window before? :-)
The expression t-[t(2:end),0] executes the difference among each terms of the t vector.
Considering t = [0, 0, 1, 0, 1, 0, 0, 1, 0];
the expression t-[t(2:end),0] gives as result [0 -1 1 -1 1 0 -1 1 0]
so it computes:
0-0 = 0
0-1 = -1
1-0 = 1
and so on
Why didn't I use the Command Window before? :-)
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