Help! Inverse of Squeeze

[Dennis Wong]

I squeezed a 3 dimension single column(:,1,3) Matrix, to a single
dimension 3 column (:,3,1) matrix, Question is how can I now after
processing, change it back to 3 dimension single column Matrix?

P/S: A(:,:,1) = [1;0;1]
A(:,:,2) = [1;1;1]
SQUEEZE(A) ;
gives A = [1 1
0 1
1 1]

Thanks in advance.

====================================================
Dennis Wong
Signal Processing & Communication Division
Department of Electrical Engineering & Electronics
University of Liverpool
Brownlow Hill
Liverpool L69 3BX
Email: M.L.D...@liv.ac.uk Tel: 0151-7944541
====================================================
A year spent in Artificial Intelligence is enough
for one to believe in God.

[Peter J. Acklam]

Dennis Wong <M.L.D...@liv.ac.uk> writes:
>
> I squeezed a 3 dimension single column(:,1,3) Matrix, to a single
> dimension 3 column (:,3,1) matrix, Question is how can I now after
> processing, change it back to 3 dimension single column Matrix?
>
> P/S: A(:,:,1) = [1;0;1]
> A(:,:,2) = [1;1;1]
> SQUEEZE(A) ;
> gives A = [1 1
> 0 1
> 1 1]

The "inverse" of SQUEEZE is RESHAPE. You need to specify the array
you want to "unsqeeze" and the size the array had before it was
squeezed:

A(:,:,1) = [1;0;1];

A(:,:,2) = [1;1;1];

S = size(A); % size before squeezing
B = squeeze(A); % squeeze
C = reshape(B, S); % "unsqueeze"

» isequal(A, C)

ans =

1

Peter

--
function Y = rot90(X, N); s=size(X); d=ndims(X); i={':'}; i=i(ones(d, 1), 1);
%ROT90 Rotate an array X, N*90 degrees counterclockwise along all dimensions.
N = N-4*floor(N/4); if (N==1)|(N==2), i{2} = s(2):-1:1; end; if (N==2)|(N==3)
i{1}=s(1):-1:1; end; Y=X(i{:}); if (N==1)|(N==3), Y=permute(Y,[2 1 3:d]); end

[Sri Kumar Kanajan]

s=squeeze(A)

» reshape(s,6,1)

ans =

1
0
1
1
1

1

Dennis Wong wrote:

> I squeezed a 3 dimension single column(:,1,3) Matrix, to a single
> dimension 3 column (:,3,1) matrix, Question is how can I now after
> processing, change it back to 3 dimension single column Matrix?
>
> P/S: A(:,:,1) = [1;0;1]
> A(:,:,2) = [1;1;1]
> SQUEEZE(A) ;
> gives A = [1 1
> 0 1
> 1 1]
>

[Peter J. Acklam]

Dennis Wong wrote:
>
> I squeezed a 3 dimension single column(:,1,3) Matrix, to a single
> dimension 3 column (:,3,1) matrix, Question is how can I now after
> processing, change it back to 3 dimension single column Matrix?
>

> [snip]

(A little pedantic here perhaps.) I believe that in Matlab lingo,
a matrix can not have more than 2 dimensions. Arrays, however, can
have an arbitrary number of dimensions. Thus, A in the example above,
is an array, but not a matrix.

Sri Kumar Kanajan <sk...@doc.ic.ac.uk> writes:
>
> s=squeeze(A)
>
> » reshape(s,6,1)
>
> ans =
>
> 1
> 0
> 1
> 1
> 1
> 1

This is a single column array, but it doesn't have 3 dimensions (as
asked for by the original poster)...

Peter

--
disp(reshape(cat(5,cat(4,cat(3,cat(2,'Ju','st'),cat(2,' a','no')),cat...
(3,cat(2,'th','er'),cat(2,' M','at')),cat(4,cat(3,cat(2,'la','b '),...
cat(2,'ha','ck')),cat(3,cat(2,'er',' '),cat(2,' ',' '))))),1,32))