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Partial fraction expansion
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Andreas Kochenburger
Aug 26, 1998, 3:00:00 AM8/26/98
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This is certainly a newbie question, but I could not solve it with the
Scilab manuals - and it has been a long time since my university years
;->
Scilab manuals - and it has been a long time since my university years
;->
How can I compute the partial fractions coefficients with Scilab?
I.e. (s+5)/(s^2+3s+2) can be transformed into 4/(s+1)-3/(s+2). The
roots() function gives me -1 and -2 correctly for the denominator. But
how can I compute the 4 and -3?
Andreas
++ If you prefer to reply by email, please replace
++ in the address: no -> khe, spam -> scn
Andreas Kochenburger
Aug 26, 1998, 3:00:00 AM8/26/98
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Sorry :-)
I just found pfss() and it worked. Great!
I just found pfss() and it worked. Great!
ahmed...@gmail.com
Oct 21, 2013, 2:56:29 PM10/21/13
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On Wednesday, August 26, 1998 2:00:00 AM UTC-5, Andreas Kochenburger wrote:
> This is certainly a newbie question, but I could not solve it with the
> Scilab manuals - and it has been a long time since my university years
> ;->
>
> How can I compute the partial fractions coefficients with Scilab?
> I.e. (s+5)/(s^2+3s+2) can be transformed into 4/(s+1)-3/(s+2). The
> roots() function gives me -1 and -2 correctly for the denominator. But
> how can I compute the 4 and -3?
>
> Andreas
>
> This is certainly a newbie question, but I could not solve it with the
> Scilab manuals - and it has been a long time since my university years
> ;->
>
> How can I compute the partial fractions coefficients with Scilab?
> I.e. (s+5)/(s^2+3s+2) can be transformed into 4/(s+1)-3/(s+2). The
> roots() function gives me -1 and -2 correctly for the denominator. But
> how can I compute the 4 and -3?
>
> Andreas
>
> ++ If you prefer to reply by email, please replace
> ++ in the address: no -> khe, spam -> scn
to create a PFE in scilab I use the following scirpt and you can modify it based what you have
> ++ in the address: no -> khe, spam -> scn
s = %s;
num =1;
den =(s^2+1) *(s^2+4);
tf=num/den;
pfe=pfss(tf)
felipe...@gmail.com
Oct 7, 2017, 2:22:34 PM10/7/17
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Em quarta-feira, 26 de agosto de 1998 04:00:00 UTC-3, Andreas Kochenburger escreveu:
> This is certainly a newbie question, but I could not solve it with the
> Scilab manuals - and it has been a long time since my university years
> ;->
>
> How can I compute the partial fractions coefficients with Scilab?
> I.e. (s+5)/(s^2+3s+2) can be transformed into 4/(s+1)-3/(s+2). The
> roots() function gives me -1 and -2 correctly for the denominator. But
> how can I compute the 4 and -3?
>
> Andreas
>
> ++ If you prefer to reply by email, please replace
> ++ in the address: no -> khe, spam -> scn
https://eletricacomscilab.blogspot.com.br/2017/09/fracoes-parciais.html
> Scilab manuals - and it has been a long time since my university years
> ;->
>
> How can I compute the partial fractions coefficients with Scilab?
> I.e. (s+5)/(s^2+3s+2) can be transformed into 4/(s+1)-3/(s+2). The
> roots() function gives me -1 and -2 correctly for the denominator. But
> how can I compute the 4 and -3?
>
> Andreas
>
> ++ If you prefer to reply by email, please replace
> ++ in the address: no -> khe, spam -> scn
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