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Solving log equations, how?

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Jeffrey A. Soesbergen

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Aug 6, 1998, 3:00:00 AM8/6/98
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How can I solve the following exponential equations:

1. log3 x=-2

2. log x + log (x+3) = 1

Can anyone tell me how to solve these in Mathematica?


Arnoud Buzing

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Aug 11, 1998, 3:00:00 AM8/11/98
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You can solve equations in Mathematica with the Solve[] command. It
takes two arguments: the equation you want to solve and the variable
you want to solve for. In your case the expressions to evaluate are:

Solve[Log[3 x] == -2, x] (followed by shift-enter)

Solve[Log[x] + Log[x + 3] == 1, x] (followed by shift-enter)

You need to use == instead of = to indicate equality; the = is used for
assignment.

---
Arnoud


Bruce H. Williams

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Aug 11, 1998, 3:00:00 AM8/11/98
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Try

Solve[Log[3,x]==2,x]

Bruce Williams

Jeffrey A. Soesbergen wrote in message
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