1. log3 x=-2
2. log x + log (x+3) = 1
Can anyone tell me how to solve these in Mathematica?
You can solve equations in Mathematica with the Solve[] command. It
takes two arguments: the equation you want to solve and the variable
you want to solve for. In your case the expressions to evaluate are:
Solve[Log[3 x] == -2, x] (followed by shift-enter)
Solve[Log[x] + Log[x + 3] == 1, x] (followed by shift-enter)
You need to use == instead of = to indicate equality; the = is used for
assignment.
---
Arnoud
Solve[Log[3,x]==2,x]
Bruce Williams
Jeffrey A. Soesbergen wrote in message
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