Hi,
The given example was just to illustrate. In the original problem, I
cannot specify the region function. Also,
I have two tables t1 and t2 with a finite number of points, and I use
ListContourPlot with the option Contours -> {0} to see the contours at
z = 0. The solution to my problem occurs when both t1 and t2 intercept
at z = 0, as in the example given.
I can reformulate my problem in the following way: Given some contour plot
p0 = ListContourPlot[Table[Sin[3 x*y], {x, -3, 3, .1}, {y, -3, 3,
.1}], Contours -> {0}, ContourShading -> False,
DataRange -> {{-3, 3}, {-3, 3}}, ContourStyle -> Black];
How to extract the x and y coordinates of the plot p0 in the form of a
list of values t0 = {{x1,y2},{x2,y2},....} . ??
I found an old thread (mg98726) involving the same issue, but the
answer (mg98760) doesn't help much.
Thanks in advance.
Luiz
On Wed, May 1, 2013 at 9:56 AM, djmpark <
djm...@comcast.net> wrote:
> Do you want something like this:
>
> ContourPlot[Sin[3 x y], {x, -3, 3}, {y, -3, 3},
> Contours -> {0},
> ContourShading -> False,