my2Dtable = {{0, 0}, {1, 1}, {2, 1}, {3, 2}, {4, 5}, {5, 8}, {6, 5}, {7, 4}};
ListPlot[my2Dtable, Joined -> True, InterpolationOrder -> 2]
my3Dtable = {{0, 0, 0}, {1, 1, 1}, {2, 1, 2}, {3, 4, 3}, {5, 6, 4}, {3, 4, 5}, {2, 1, 6}, {7, 7, 7}};
ListPointPlot3D[my3Dtable]
ListPlot3D[my3Dtable]
Thanks in advance for any help
Jakub
Graphics3D[Line[my3Dtable]]
-Francesco
Just making some graphic primitives, and do it yourself, it is really easy as you can see.
my3Dtable = {{0, 0, 0}, {1, 1, 1}, {2, 1, 2}, {3, 4, 3}, {5, 6,
4}, {3, 4, 5}, {2, 1, 6}, {7, 7, 7}};
Graphics3D[
{Line[my3Dtable],
AbsolutePointSize[4],
Point /@ my3Dtable},
Axes -> True]
Or in Version 7:
Graphics3D[
{BSplineCurve[my3Dtable],
AbsolutePointSize[4],
Point /@ my3Dtable},
Axes -> True]
But I'm not certain how one obtains a smooth interpolated curve that goes
through all the points.
David Park
djm...@comcast.net
http://home.comcast.net/~djmpark/
Graphics3D[{Blue, Line[my3Dtable],
Red, AbsolutePointSize[4], Point[my3Dtable]}]
Table[Graphics3D[{Blue,
f[my3Dtable, SplineDegree -> d],
Red, AbsolutePointSize[4], Point[my3Dtable]}],
{f, {BSplineCurve, BezierCurve}},
{d, Length[my3Dtable]}] // Grid
Bob Hanlon
---- Serych Jakub <Ser...@panska.cz> wrote:
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