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# limits on symbol eigenvalues?

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### Uwe Brauer

Jun 4, 2004, 5:14:46 AM6/4/04
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Hello

I just started using mathematica. When I tried to calculate the
symbolic eigenvalues of a 16x16 matrix mathematica told me it couldn't

Is there a restriction?

Thanks

Uwe Brauer

### Curt Fischer

Jun 5, 2004, 7:49:46 AM6/5/04
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I think Mathematica couldn't do it because it is impossible to find the
symbolic roots to a sixteenth order polynomial, in general.

--
Curt Fischer

### Yasvir Tesiram

Jun 5, 2004, 8:06:19 AM6/5/04
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On Jun 4, 2004, at 3:49 AM, Uwe Brauer wrote:

> Hello
>
> I just started using mathematica. When I tried to calculate the
> symbolic eigenvalues of a 16x16 matrix mathematica told me it couldn't
>
> Is there a restriction?
>

Yes, memory usually.

Yas

### Andrzej Kozlowski

Jun 5, 2004, 7:58:54 PM6/5/04
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On 5 Jun 2004, at 20:18, Curt Fischer wrote:

> I think Mathematica couldn't do it because it is impossible to find the
> symbolic roots to a sixteenth order polynomial, in general.
>
> --
> Curt Fischer
>
>
>

Actually this is not quite true. It is certianly possible to find
symbolic roots of a polynomial od degree 16 or higher and Mathematica
can do it. (Just try it yourself). What is not possible, in general, is
to express this solution in terms of radicals, but that is quite a
different issue, unrelated to this problem.

The original question can't be answered with so little information.

Andrzej Kozlowski

### norooz...@gmail.com

May 5, 2014, 3:03:26 AM5/5/14
to
Hi,
I just start to use Mathematica, and I have exactly same problem
I really appreciate If can give me some advice.
thanks
Leyla

### David Bailey

May 12, 2014, 12:44:22 AM5/12/14
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Not every symbolic problem that you can pose has a symbolic solution.
For example, some symbolic integrals don't have symbolic solutions -
likewise for differential equations.

A symbolic eigenvalue problem of order N involves solving an N'th order
polynomial equation. Specific cases can be solved, but the general case
cannot be solved for N>=5. This restriction can in theory be relaxed (I
am not sure by how much) by the use of theta functions, though the