Every time I do this, the vertical axis goes up to 1.2, not 1 --- is
there any way to have this only go upto 1? (The function I'm plotting
goes upto 1 only.)
Cheers!
Cheers -- Sjoerd
This is the code:
PolarPlot[Sin[2 \[Theta]]^2, {\[Theta], -\[Pi]/2, \[Pi]/2},
PolarGridLines -> True, PolarAxes -> True,
PolarTicks -> {Table[i \[Degree], {i, -90, 90, 15}], Automatic},
PlotRange -> {{0, 2}, {-1, 1}}, PerformanceGoal -> "Speed",
PlotRangeClipping -> False,
PlotStyle -> {{Red, Thick, Dotted}, {Red, Thick}},
PlotLabel -> "label"]
The 'y' axis goes to 1.2; I'd like it to go to 1, and thus have the
plot peak at the outer bold line.
Thanks.
On Fri, Nov 20, 2009 at 1:12 PM, David Park <djm...@comcast.net> wrote:
> Copy as Input Text and paste the explicit code into your posting. Otherwise
> you are asking responders to guess what you did.
>
>
> David Park
> djm...@comcast.net
> http://home.comcast.net/~djmpark/
PolarAxesOrigin->{90deg,1} is great and exactly what I wanted. I will
file that support request.
Chris
On Fri, Nov 20, 2009 at 3:47 PM, Brett Champion <bre...@wolfram.com> wrote:
> On Nov 20, 2009, at 5:41 AM, fo3nix wrote:
>
>> Hi guys,
>> I am trying to polarplot a function like Sin[2 x]^2, from -Pi/2 to Pi/
>> 2, with polar ticks and gridlines enabled.
>>
>> Every time I do this, the vertical axis goes up to 1.2, not 1 --- is
>> there any way to have this only go upto 1? (The function I'm plotting
>> goes upto 1 only.)
>
> This works: PolarAxesOrigin -> {0, 1}, although I'd expect PlotRange->1 to
> work also. Can you file that with sup...@wolfram.com, please?
>
> Thanks,
>
> Brett Champion
> Wolfram Research
>
From: fo3nix [mailto:chris...@gmail.com]
Hi guys,
I am trying to polarplot a function like Sin[2 x]^2, from -Pi/2 to Pi/
2, with polar ticks and gridlines enabled.
Every time I do this, the vertical axis goes up to 1.2, not 1 --- is
there any way to have this only go upto 1? (The function I'm plotting
goes upto 1 only.)
Cheers!