See here
http://mathworld.wolfram.com/HyperbolicParaboloid.html
Two very examples follows now
In[3]:=
ParametricPlot3D[{u, v, u*v}, {u, -3, 3}, {v, -3, 3}]
In[4]:=
Plot3D[y^2/2 - x^2/3, {y, -2, 2}, {x, -3, 3}]
"Playing" with the options you can make them look
much more better.
Dimitris
Hi William
two examples:
Plot3D[x^2-y^2 ,{x,-1,1},{y,-1,1}]
or if you rotate x y:
Plot3D[x y ,{x,-1,1},{y,-1,1}]
hope this helps, Daniel
(1) the equation z=f(x,y) of a hyperbolic paraboloid (try Googling that
-- probably the first hit you'll get is to MathWorld); and
(2) how to plot a real-valued function f(x,y) of two real variables in
Mathematica.
If you're using Mathematica 6, open the Documentation Center, go to the
section "Visualization and Graphics", click the link "Function
Visualization" there, and inspect the list of functions you'll see on
the guide page that opens; it should be obvious from the descriptions
(and even the names, perhaps) which one to use, and if you click that
name, it will give you a page about that function with lots of examples
(including, as an example of using a mesh, a hyperbolic paraboloid!).
If you're using Mathematica 5.2, open the Help Browser and in the list
in the first panel on the first tab (Built-in Functions), click
"Graphics and Sound". In the list that now appears in the second panel
you'll see an obviously relevant item, "3D Plots". Click that link. In
the third panel you'll see a list of three functions. Try the first of
those. Open the "Further Examples" at the bottom of the page about that
function.
William S. wrote:
> Does anyone know how to plot a hyperbolic paraboloid?
>
>
--
Murray Eisenberg mur...@math.umass.edu
Mathematics & Statistics Dept.
Lederle Graduate Research Tower phone 413 549-1020 (H)
University of Massachusetts 413 545-2859 (W)
710 North Pleasant Street fax 413 545-1801
Amherst, MA 01003-9305
ContourPlot3D[
x^2 - y^2 + z^2 == 1, {x, -2, 2}, {y, -2, 2}, {z, -2, 2}]
???
Regards
Jens
6.0 for Mac OS X x86 (32-bit) (June 19, 2007)
ParametricPlot3D[{u, v, u*v}, {u, -1, 1}, {v, -1, 1}]
With[{a = 1, b = 1},
ContourPlot3D[
z == y^2/b^2 - x^2/a^2, {x, -1, 1}, {y, -1, 1}, {z, -1, 1}]]
Bob Hanlon