Parsing dig output consistently

[Anand Buddhdev]

Hello people,

I've been trying to figure out how to use dig in a shell script to send
a bunch of queries, and then parse the output with awk. I have a file
called "myzones" containing the zones I want to query:

example.com
example.org
example.net

If I run:

dig @server -t soa +norec +noall +question +answer -f myzones

I get output like this:

;example.com. IN SOA
example.com. 3600 IN SOA ( ... )
;example.org. IN SOA
example.org. 3600 IN SOA ( ... )
;example.net. IN SOA
example.net. 3600 IN SOA ( ... )

What I'm missing is the header and flags section, because I also want to
see the RCODE and the flags. However, I don't know which option to dig
will give me:

;; Got answer:
;; ->>HEADER<<- opcode: QUERY, status: NOERROR, id: 41562
;; flags: qr aa; QUERY: 1, ANSWER: 1, AUTHORITY: 1, ADDITIONAL: 1
;example.com. IN SOA
example.com. 3600 IN SOA ( ... )

Actually, I am not really interested in the answer either. All I want
are lines showing me the RCODE and the question, which I can match up
and determine whether a server is returning NOERROR, REFUSED or SERVFAIL
for a given zone. Is this possible?

Regards,

Anand

[Mark Andrews]

awk '$5 == "status:" { rcode = $6 } $3 == "SOA" { print $1, rcode }'

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[Anand Buddhdev]

On 17/09/2014 13:57, Mark Andrews wrote:

Hi Mark,

> awk '$5 == "status:" { rcode = $6 } $3 == "SOA" { print $1, rcode }'

So with "+noall +comments +question" and this bit of awk, I can get a
pretty list containing ";zone RCODE," pairs :)

Thanks!

Anand