can't understand for String.delete
Ruby Newbee
its arguments deleted. Uses the same rules for building the set of
characters as +String#count+.
"hello".delete "l","lo" #=> "heo"
"hello".delete "lo" #=> "he"
"hello".delete "aeiou", "^e" #=> "hell"
"hello".delete "ej-m" #=> "ho"
What does this mean?
I can't understand for the rules.
Thanks.
Jesús Gabriel y Galán
What it means is that it builds a character set performing the
intersection of all arguments to the method. So if you do
s.delete("h", "he") the intersection of the arguments is "h", because
it's the only one present in all arguments. If the arguments don't
intersect nothing is deleted:
irb(main):001:0> "hello".delete "h", "e"
=> "hello"
The other part of the explanation means that as the documentation for
String#count says
(http://ruby-doc.org/core/classes/String.html#M000834):
"Any other_str that starts with a caret (^) is negated. The sequence
c1—c2 means all characters between c1 and c2. "
This means that s.delete("^aeiou") will remove all consonants and
leave the vocals, and that s.delete("a-m") will delete all characters
between "a" and "m":
irb(main):002:0> "hello".delete "a-m"
=> "o"
irb(main):003:0> "hello".delete "^aeiou"
=> "eo"
irb(main):004:0>
Hope this helps,
Jesus.
Ruby Newbee
never saw this syntax in my other languages of programming, :-)
2009/11/24 Jesús Gabriel y Galán <jgabrie...@gmail.com>:
Jesús Gabriel y Galán
> ah~ thanks, I got it.
> never saw this syntax in my other languages of programming, :-)
"^" for negating and "-" for character ranges are usual syntax of
regular expressions.
Jesus.
