datetime.timedelta.replace?

[Skip Montanaro]

Datetime objects have a replace method, but timedelta objects don't.
If I take the diff of two datetimes and want to zero out the
microseconds field, is there some way to do it more cleanly than this?

delta = dt1 - dt2
zero_delta = datetime.timedelta(days=delta.days, seconds=delta.seconds)

I guess that's not bad, but replace() seems cleaner (or at least more
congruent with datetime objects).

Skip

[Joshua Landau]

Maybe one of

delta - datetime.timedelta(0, 0, delta.microseconds)

or

delta - delta % datetime.timedelta(seconds=1)

is clearer.