Google Groups no longer supports new Usenet posts or subscriptions. Historical content remains viewable.
Dismiss

Encoding Symbol glyphs into Latin 1 set

0 views
Skip to first unread message

Timothy Hayes

unread,
Feb 21, 1989, 2:37:00 PM2/21/89
to

Does aynone know of a way to encode a glyph from the Symbol set
into the Standard set? I have tried changing the encoding
array in ReencodeSmall (from the cookbook) to use a Symbol
character, but a blank is always rendered instead of the desired
Symbol character. Presumably someone has solved this problem,
since the Adobe latin 1 character set does not conform to the
ISO standard.

Tim Hayes
Apollo Computer
---------------

John Bowler

unread,
Feb 27, 1989, 12:39:00 PM2/27/89
to
In article <890223134...@decwrl.dec.com>, batch...@hannah.dec.com (Ned Batchelder, PostScript Eng.) writes:
>
> >> .. the Adobe latin 1 character set does not conform to the
> >> ISO standard.
>
> In what way does Adobe's ISOLatin1Encoding encoding vector not conform to
> the ISO standard?

Is this a different encoding to that on page 252 of the Red book? If so -
where is it defined? If not the answer to the question is that it lacks all
of the `composite' characters from the ISO-Latin1 (ie all the alphabetics with
accents) and has the ANSI currency symbol in a different place (the same place
as in the DEC multinational character set, which is only slightly different
from ISO-Latin1...) There are also several additions (eg perthousand) and
ommissions (eg the fractions and plusminus - which is in the Symbol encoding).

I believe that the answer to the original question is that the the character
from a suitable symbol font must be extracted and placed in the new font
along with the encoding which references it - all that the encoding says is
how to map byte values in strings into the name of a character definition
in the font dictionary. Therefore if the encoding:-

177 --> plusminus

is added to the encoding vector a character (plusminus) must also be added
to the font dictionary (in the CharStrings dictionary).

John Bowler (jbo...@acorn.co.uk)

0 new messages