I have made a very simple JavaAjax like this:
<div class="iconbox" onmouseover="InProcess('my text', 'inprocess', 'In
Process');"></div>
<div id=inprocess"></div>
and it opens a small windows with the 'my text' in it, in a div below the
icon.
BUT... how do i close it again with onmouseout ?
Is there a simple way ?
And 'JavaAjax' is NOT the correct term. It's Ajax. You are using
JavaScript to perform Ajax.
> On Aug 18, 9:01 am, "EnjoyNews" <mh-nyhe...@mail.dk> wrote:
>> Hi
>>
>> I have made a very simple JavaAjax like this:
>> <div class="iconbox" onmouseover="InProcess('my text', 'inprocess',
>> 'In Process');"></div>
>> <div id=inprocess"></div>
>>
>> and it opens a small windows with the 'my text' in it, in a div below
>> the icon.
>>
>> BUT... how do i close it again with onmouseout ?
>>
>> Is there a simple way ?
[Please do not toppost on usenet]
> Why are you opening a window. Do you understand what Ajax is or are
> you debugging or somthing.
>
> And 'JavaAjax' is NOT the correct term. It's Ajax. You are using
> JavaScript to perform Ajax.
Indeed.
However a window "in a div" is not a window,
so the OP is not opening a window.
--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)