[Q] Java syntax to append a "EOF" to the end of a string?

[Stephen Chan]

Hello:

Does anyone know what's the Java syntax to append
a "EOF" character to the end of a string?

String mystring;
mystring = mystring + ?????;

Thanks
Stephen

[Tov Are]

Try String.length(). You don't need a eof character in Java (although they
probably have zero termination internally).
Stephen Chan wrote in message
<01bd20ff$072115c0$1bf9...@direct.ca.direct.ca>...
[cut]

[Roedy Green]

Tov Are wrote:
>although they probably have zero termination internally).

Have a look at the source code for String. Strings are actually substrings
of char[] consisting of an offset and length. Several String constants can
share a common base char[].

Unlike C/C++, Java keeps track of how long its strings are rather than
scanning for a terminating null.

For the JAVA GLOSSARY and the CMP Utilities: http://oberon.ark.com/~roedy
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[Daniel Barclay]

Stephen Chan wrote:
> ...

> Does anyone know what's the Java syntax to append
> a "EOF" character to the end of a string?

What end-of-file character?

Daniel

[Roedy Green]

Daniel Barclay wrote:
>> Does anyone know what's the Java syntax to append
>> a "EOF" character to the end of a string?

if you mean chr$(26) you could do it with octal notation:

String s = "abc" + "\032";

if you mean chr$(0), you don't need it for Java since it tracks it own
string lengths. If you want a trailing null for native C, you could use
the same technique:

String s = "abc\000";

[Daniel Barclay]

Roedy Green wrote:
>
> Daniel Barclay wrote:
> >> Does anyone know what's the Java syntax to append
> >> a "EOF" character to the end of a string?
>

> ...

Hey. Don't quote me out of context.

I didn't ask that question; your message could imply that I did.

Daniel