operator[][]

[asetof...@gmail.com]

Is it possible to define operator operator[][]?
(and operator[][][] and operator[][][][])

T& operator[](int i)
{}
Seems the only that compile

[red floyd]

Only if T is either a pointer, array, or some type that has operator[]()
defined.

[asetof...@gmail.com]

Stefan wrote:
<< it
can be demonstrated by a one-liner (80 characters):

struct s{ s & operator[]( int ){ return *this; }}; int main(){ s{}[ 0 ][ 0 ]; }
>>
What does it mean s{}?

I think i can easily resolve this
call as function M.elm(i, j)
at place of M[i][j]...

[Nobody]

On Tue, 05 May 2015 15:00:38 -0700, asetofsymbols wrote:

> Is it possible to define operator operator[][]?
> (and operator[][][] and operator[][][][])

No. But you can define operator[] such that its return type supports
subscripting (either a pointer or a class which itself implements operator[]).

Alternatively, you could use operator() for array acess, so a[i][j][k]
becomes a(i,j,k).

[Juha Nieminen]

To achieve that syntax, T must be something that itself supports
operator[]. It's perfectly possible, you just have to define it
more recursively.

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