Function overloading problem (global versus member)

[JiiPee]

I dont understand why that foo(p); does not find the correct foo-version
automatically even though its obvious it should call the global
foo(const Player& player);. Can anybody please explain why its trying to
call the foo(const std::string& name, int a) version (and causing a
compilation error-) even though there is perfect match with the global
version?

Just would like to know the theoretical reason for this. (I know
::foo(p);  solves it, but is that the only solutions? I would rather not
put those :: ).

thanks


class Player
{
};

void foo(const Player& player);

class A
{
public:
    std::string name_;
    void foo(const std::string& name, int a)
    {
        Player p;
        foo(p);
    }
};

void foo(const Player& player)
{

}

int  main() {
    A a;
    a.foo("sdf", 9);
    return 0;
}

[JiiPee]

On 31/12/2017 22:46, Stefan Ram wrote:
> JiiPee <n...@notvalid.com> writes:
>> void
> ...
>>     void
> The second declaration appears in a scope that is nested in
> the scope of the first declaration. Therefore, the second
> declaration /hides/ the outer declaration of the same name
> [basic.scope.hiding], and hidden names do not take part in
> name resolution.
>
ok, thanks, I thought its something like this.