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stream modifiers
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ruben safir
Dec 4, 2016, 5:19:17 AM12/4/16
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can on make std::cout format a uinit_8 as an integer type of 8 bits - or
just print a number at least.
just print a number at least.
Bo Persson
Dec 4, 2016, 5:38:39 AM12/4/16
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On 2016-12-04 11:19, ruben safir wrote:
> can on make std::cout format a uinit_8 as an integer type of 8 bits - or
> just print a number at least.
>
The problem is that the 8-bit type is just a typedef for unsigned char.
> can on make std::cout format a uinit_8 as an integer type of 8 bits - or
> just print a number at least.
>
So the I/O treats it like a character. Because it is.
To display it as an integer, you will have to cast it to unsigned int.
Bo Persson
Alf P. Steinbach
Dec 4, 2016, 6:33:54 AM12/4/16
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On 04.12.2016 11:19, ruben safir wrote:
> can on make std::cout format a uinit_8 as an integer type of 8 bits - or
> just print a number at least.
The shortest way is to add a `+` in front of it.
> can on make std::cout format a uinit_8 as an integer type of 8 bits - or
> just print a number at least.
- Alf
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