Since (at least now) after I have sufficiently explained exactly how the
abstract model of computation defined by the x86 language would have
access to unlimited memory is blatantly obvious, some of the more rude
critiques may seem quite foolish.
"To show that something is Turing-complete, it is enough to show that it
can be used to simulate some Turing-complete system. For example, an
imperative language is Turing-complete if it has conditional branching
(e.g., "if" and "goto" statements, or a "branch if zero" instruction;
see one-instruction set computer) and the ability to change an arbitrary
amount of memory..."
https://en.wikipedia.org/wiki/Turing_completeness
When we assume that the above is correct then we can conclude that the
x86 language is fully Turing complete by having control flow and data
access to unlimited memory and conditional branch instructions that can
be executed from anywhere in this memory.