Newsperson HW

[Nicholas Woo]

All, here are my solutions to the Newsperson HW, let me know if anyone obtained anything different:

a.) Cu = $0.73 per glass

b.) Co = $0.07 per glass

c.) Critical Ratio = .9125

d.) 4,000 + .9125 (4,999 - 4,000) = 4,911.59 / 100 = 49.12 Kegs <--not 100% sure on this one

e.) Historical data is not always a representative indicator of future demand since other unknown variables that could affect future outcomes may exist.

f.) 1,000 + .9125(7,000 - 1,000) = 6,475 / 100 = 64.75 Kegs

g.) X = 5,678 where P(X <=5,678) = 0.9125 ; 5,678 / 100 = 56.78 kegs

[alex smirnov]

Hi,

I got the same results for a-c, e

for (d), my answer is 60 kegs (round up).  Based on cumulative probability, there is roughly a 91% chance of selling 5,999 glasses or less.  I then assume that within the 5,000-5,999 range the # of glasses sold is uniformly distributed  =>   5,000+.9125*1000 = 5912.5  => buy 60 kegs

for (f) I got 65 kegs (round up)

for (g) I used excel  =>      "=NORMDIST(57,50,5,TRUE)"  is 0.919243  => buy 57 kegs.

[Michelle Nunes]

I agree with Alex. I would order 5,000 - 5,999 kegs :)

[Michelle Nunes]

cups* lol

[Xiuya Li]

Hi All,

Please see my attachment for R_X bar charts homework, let me know whether you got the same.

Thanks!
Ted Li

 

By the way, How can I change the subject for this existing email chain, or how do I attach a file from a new post (could not find a place called attach?).

[Nicholas Woo]

I got the same.

[Tushar K]

Got a question...

After calculating the population-sigma and sigma for the first data set, we don't have to calculate it again for the other sets?

LCL-X, UCL-X, LCL-R and UCL-R remains same in your case.

Thanks,

Tushar

[Nicholas Woo]

That's correct. We're using the upper and lower control limits established from the benchmark data to evaluate the stability of the sample data.