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chisom dike Onwuegbuzie
Jun 24, 2014, 2:23:26 AM6/24/14
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please how can i round up a float value to a 2 decimal places
Shai Almog
Jun 24, 2014, 1:02:30 PM6/24/14
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int i = (int)(floatNumber * 100);
float f = ((float)i) / 100.0f;
float f = ((float)i) / 100.0f;
drbest...@gmail.com
Jun 28, 2014, 3:19:16 AM6/28/14
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On Tuesday, June 24, 2014 6:02:30 PM UTC+1, Shai Almog wrote:
> int i = (int)(floatNumber * 100);
> float f = ((float)i) / 100.0f;
> int i = (int)(floatNumber * 100);
> float f = ((float)i) / 100.0f;
Are you trying to say I Should be dividing each float number with 100.0f to get two decimal places of that float number.
Shai Almog
Jun 28, 2014, 12:23:51 PM6/28/14
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Multiply by 100 first, round, then divide by 100.
drbest...@gmail.com
Jun 30, 2014, 4:25:15 AM6/30/14
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On Saturday, June 28, 2014 5:23:51 PM UTC+1, Shai Almog wrote:
> Multiply by 100 first, round, then divide by 100.
> Multiply by 100 first, round, then divide by 100.
Ok tanx
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