Into The Black Download Torrent
Christal Rasband
Discussion and conclusions: The findings provide insight into what black and minority ethnic people regard as the barriers to, and facilitators of self-management, as opposed to what health professionals, policy makers and trial researchers may have assumed. Recognition of the views of people with diabetes is essential for the design and delivery of patient-centred care and policies.
I'm very new to photoshop so slowly working my way round it. Apologies for asking what may seem a very simple question. I am playing with an image and all i am looking to do is just blend the image into my black background. I just cant figure out how to achieve this. I have my image and an example image below to what i am trying to achieve. Ideally i want to blend it into the background to hide the straight edge on the right hand side of the image.
Where the mask is white it will show the image on the layer. Where the mask is black it will hide the image and allow the black layer below to show through. Grey is semi transparent. So switch between the black and white brush until you have the effect you want.
You will first need to convert your image layer to a normal layer if you image is in Photoshop background layer. No layer can be move below a background layer and background layer can not be masked for it does not support transparency. If you hold down the Alt or option key and click on the add layer mask icon in the layers palette the targeted Background will be converted to a normal layer and a hide all layer mask will be added. The layer mask will be Photoshop's current target and the layer will look empty. Switch to a white soft large paint brush and paint over you subject to reveal your animal subject in the masked layer. Then Hold down the Crtr or CMD key and click on the Add layer icon in the layers palette to add an empty layer below your image layer. Fill that layer with the background color you want like black.
Something else I use a lot is Camera RAW > fx > Post Crop Vignette which has a lovely soft gradient. If you make the layer a Smart Object, this is also non-destructive, but is limited in how far the vignette can extend into the scene
There may already be this question being answered somewhere else but I did not see it. I would like to be able to take photographs and change them into black and white line drawings but keeping a lot of the detail which gets lost in just "tracing" the image as well as I need rather solid lines and often they don't turn out solid enough...I am pretty illiterate when it comes to these programs so if you have a very simple (dumb downed) way to do so I would SO appreciate it!! Thank you!!
Welcome to the Forums @bob prince?! What a nice post for your first! And what a nice surprise for me!! I was fiddling just yesterday with an image that was resisting my every effort (entirely black background with a very lacy foreground). I used your method and -- as you so aptly state -- Voilà. Thank you. It worked like a charm.
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I know that if one astronaut falls into a black hole, then a distant observer will see him take an infinite amount of time to reach the event horizon (provided the observer can see light of arbitrarily large wavelengths).
No. He would see that only if he stopped falling close to and above the horizon, by thrusting or going into orbit, say. (No stable orbits exist too close.) An observer falling straight in won't see time speed up above him.
A way to visualize this is with the river model of black holes (googleable). An observer who flows with the river, by falling straight inward toward a center of gravity, doesn't notice time speed up above him. To notice that the astronaut must "fight the current" somehow. By fighting the current the astronaut can receive information that is "flowing with the river" faster than normal.
We will see the rest of the universe speed up more and more, and when we reach the event horizon, we will stop observing anything. Only when we leave the black hole (somehow magically) our time dilation begins to dilate less, and we will begin to experience something again: The rest of the universe will seem - to us - to have sped up, and then aged instantaneous in this interval of perfect dilation, and then speed less and less until our dilation becomes closer and closer to that of the referenced frame.
I am making a sticker for Macbook Pro. The image is of the Joker and it is in black and white. Now I wanna make it in black and transparent so that when I stick it to the back of the laptop you could still see the silver underneath. I included the image here and another one( Harry Potter) as a reference.
The event horizon of a black hole is where gravity is such that not even light can escape. This is also the point I understand that according to Einstein time dilation will be infinite for a far-away-observer.
If this is the case how can anything ever fall into a black hole. In my thought experiment I am in a spaceship with a powerful telescope that can detect light at a wide range of wavelengths. I have it focused on the black hole and watch as a large rock approaches the event horizon.
Am I correct in saying that from my far-away-position the rock would freeze outside the event horizon and would never pass it? If this is the case how can a black hole ever consume any material, let alone grow to millions of solar masses. If I was able to train the telescope onto the black hole for millions of years would I still see the rock at the edge of the event horizon?
First, let's imagine a classical black hole. By "classical" I mean a black-hole solution to Einstein's equations, which we imagine not to emit Hawking radiation (for now). Such an object would persist for ever. Let's imagine throwing a clock into it. We will stand a long way from the black hole and watch the clock fall in.
I had the opportunity to chat to a cosmologist about this subject a few months ago, and what he said was that this red-shifting towards undetectability happens very quickly. (I believe the "no hair theorem" provides the justification for this.) He also said that the black-hole-with-an-essentially-undetectable-object-just-outside-its-event-horizon is a very good approximation to a black hole of a slightly larger mass.
(At this point I want to note in passing that any "real" black hole will emit Hawking radiation until it eventually evaporates away to nothing. Since our clock will still not have passed the event horizon by the time this happens, it must eventually escape - although presumably the Hawking radiation interacts with it on the way out. Presumably, from the clock's perspective all those billions of years of radiation will appear in the split-second before 12:00, so it won't come out looking much like a clock any more. To my mind the resolution to the black hole information paradox lies along this line of reasoning and not in any specifics of string theory. But of course that's just my opinion.)
Now, this idea seems a bit weird (to me and I think to you as well) because if nothing ever passes the event horizon, how can there ever be a black hole in the first place? My friendly cosmologist's answer boiled down to this: the black hole itself is only ever an approximation. When a bunch of matter collapses in on itself it very rapidly converges towards something that looks like a black-hole solution to Einstein's equations, to the point where to all intents and purposes you can treat it as if the matter is inside the event horizon rather than outside it. But this is only ever an approximation because from our perspective none of the infalling matter can ever pass the event horizon.
Assume the object falling in is a blue laser that you launched directly (radially) towards the Schwarzchild (non-rotating) black hole that is aimed directly at you and that you are far from the black hole. The massive object is the laser itself, the light that you are watching is your way to "see" the object as it approaches the event horizon.
First of all just because the laser is moving away from you it will be slightly red-shifted just by the Doppler effect. As it approaches the black hole that slight red-shift will become more and more significant. The laser light will go from blue, to green, to yellow, to red, to infrared, to microwave and to longer and longer wavelength radio waves as it appears to approach the event horizon from your point of view. Also the number of photons it emits per second (as you detect them) will decrease with time as the horizon is approached. This is the dimming effect - as the wavelength increases, the number of photons per second will decrease. So you will have to wait longer and longer between times when you detect the longer and longer wavelength radio waves from the blue laser. This will not go on forever - there will be a last photon that you ever detect. To explain why, let's look at the observer falling in.
So, I claim that the laser does disappear from an outside observer's point of view. Note that trying to "illuminate" the object near the event horizon by shining a different laser on the object and looking for scattered photons will not work. (It will not work even if you throw the second laser in to try to illuminate the first laser.) From the point of view of the laser that fell in, these photons will only hit the laser after it has already crossed the event horizon and therefore the scattered light cannot escape from the black hole. (In fact, if you wait too long before you try to illuminate the object, the infalling laser will have already hit the singularity at the center of the black hole.) From the outside observer's "point of view" (but he cannot "see" this), the infalling laser and the photons that are trying to illuminate the laser will get "closer and closer" to each other as they get frozen on the event horizon - but they will never interact and there will never be a scattered photon that you might try to detect.
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