What does "Map literal must contain an even number of forms" mean?

[bill nom nom]

;; This works,
(hash-map :a 1 :b 2 )

;; Here's another way to create a hash map, this won't work because map
;; literal must contain even number of forms
 {hash-map :c "Turd" :d "More Turd"}

What does "Map literal must contain an even number of forms" mean?

[lvh]

That’s not how you use a map literal. That’s trying to create a map of hash-map to :c, “Turd” to :d, and “More turd” to…. nothing — which is why it breaks. You need an even number of forms because you need a value associated with every key. I don’t know where you got that comment about another way to create a hash map, but it is incorrect.

lvh

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[Mark Nutter]

​In other languages, curly braces are used to enclose executable statements, so something like { println("Hello world\n"); }​ makes sense. In Clojure, however, curly braces are used to enclose a list of key/value pairs, aka a map. So when  you say 

{hash-map :c "Turd" :d "More Turd"}

you are creating a data structure with 2 and a half pairs. The first pair uses the function hash-map as the key, and :c as the value; then "Turd" as the next key and :d as the value; then "More Turd" as the last key, and no value, causing the error.

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[Karel Miarka]

(hash-map :a 1 :b 2) is equivalent of {:a 1 :b 2} so this will work: {:c "Turd" :d "More Turd"}

[larry google groups]

This is all you need:

{:c "Turd" :d "More Turd"}

(defn turd [] 
{:c "Turd" :d "More Turd"})

[larry google groups]

This:

(defn turd [] 
{:c "Turd" :d "More Turd"})

Would return this map:

{:c "Turd" :d "More Turd"}

This:

(defn config [username password] 
{:u username :p password})

returns a map based on the function arguments.

[bill nom nom]

Ok, I get it now. Thanks!