the only solution comes to mind is a two pass partition.
ie
(flatten (partition 1 2 dl)) for the first list
and (flatten (partition 1 2 (rest dl))) for the 2nd list.
2009/12/2 Konrad Kułakowski (kony) <
kulak...@gmail.com>:
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Omnem crede diem tibi diluxisse supremum.