Can't define method not in interfaces...what is this?

[Jim - FooBar();]

I'm struggling to find an explanation for this...

what on earth is this? what does it mean?

Can anyone clarify where this exception comes from?

Jim

[Karsten Schmidt]

It might mean you're probably having a typo somewhere you're trying to
extend a protocol like so:

(defprotocol IFoo
(foo [x]))

(defrecord MyFoo [x y]
IFoo
(fooo [x] x)) ; note misspelled foo

;; CompilerException java.lang.IllegalArgumentException:
;; Can't define method not in interfaces: fooo, compiling:(NO_SOURCE_PATH:1)

Correct? K.

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[Jim - FooBar();]

Ok that was frustrating! I had a docstring like below which apparently
is not allowed.

(defrecord MyFoo [x y]
IFoo

(foo "returns arg" [x] x)) ;


phew... :)

thanks!

Jim