UNALIGNED_LOAD64 a puzzle?

[szxia...@gmail.com]

static uint64 UNALIGNED_LOAD64(const char *p) {
  uint64 result;
  memcpy(&result, p, sizeof(result));
  return result;
}

 

why not

 memcpy(&result, &p, sizeof(result));

 

 

memcpy(&result, p, sizeof(result)  only copy character values cutted 64 bit  from p.

 memcpy(&result, &p, sizeof(result));  really copy the address 64bit value to result.

 

is realy right?

 

[tay...@gmail.com]

You are really copying data pointed to by p which might be unaligned to result. This is needed for machines that don't support unaligned access.