Asymmetric Encryption Algorithm Question

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VT

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Jul 28, 2018, 4:21:27 PM7/28/18
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How many keys are required to fully implement an asymmetric encryption algorithm with eight participants?

A. 8

B. 16

C. 28

D. 56

With Kind Regs,
V.T.

Rajan Gauchan

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Jul 28, 2018, 4:22:46 PM7/28/18
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C. 28

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Venky T

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Jul 28, 2018, 4:25:38 PM7/28/18
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THanks for your reply. I guess you used this formula right - 

n(n-1) / 2

Any other explanation...?

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Neeraj Shah

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Jul 28, 2018, 4:33:40 PM7/28/18
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 Asymmetric is always times 2 ( public/pvt key pair). So answer is 16. Symmetric is N*(N-1)/2.

C. 28

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Venky T

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Jul 28, 2018, 4:35:28 PM7/28/18
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Great, thanks for clarifying that...

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C. 28

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raazan

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Jul 28, 2018, 5:27:43 PM7/28/18
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Nick79 

Yes you are right, 
For symmetric is (N*(N-1))/2  
For Asymmetric, each participant has 2 keys, private and public key. Since the question says 8 participants so each has 2 keys summing to be having total 16 keys.

Thanks for correct answer and clarification.

C. 28

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