PS = 15.195 * VC (CD – 3.0378) + ((5.0062*10^-2) * T) – (2.6555 x 10^-4 * (T^2))
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Yes, the temp that the cider is kept. Here is the formula that is used Brew By The Numbers, Michael L. Hall, Ph.D.1995 As you can see temperature of cider is used.
- PS= Dextrose required in grams
- VC= Volume of cider
- CD= Colume of carbon dioxide
- T= Cider temperture before bottling
PS = 15.195 * VC (CD – 3.0378) + ((5.0062*10^-2) * T) – (2.6555 x 10^-4 * (T^2))
This means if CO2 is 44 grams per mole and we want to know how much 1 liter of CO2 weights at STP we can do this: 1mol CO2 at STP = 22.4 Liters as it is for all gases, and we know that CO2 = 44Grams/mol (weight) so 44 / 22.4 = 1.964 grams per liter. Therefore the density of CO2 at Standard Pressure and Temperature is 1.964g/l.
Just a few more to make sure you have it: Methane has a molecular weight of 16 (grams per mole). Calculate the volume occupied by 3.6 grams of Methane at STP. This means that 3.6 grams / (divided by) 16 grams per mole means that we're working with .225 mols of gas. Then we know that at STP the volume occupied by one mole is 22.4 liters so 22.4 * .225 = 5.04 liters.
Now that we have some what of a grasp of the relationships that gases posses, the formula that gives us the amount of pressure needed to get the volumes of CO2 required is slightly more complicated because of all the constants required, but the most popular short cut formula is as follows.
Pressure = F(Temperature, Volume) Temperature is is Fahrenheit, Volumes is in Volumes of CO2 required. Please remember your order of operations! And to convert Celsius to Fahrenheit the formula is CĄ = (FĄ - 32) x (5 / 9) . The way to do it in your head is: Centigrade to Fahrenheit double the number, subtract 10%, then add 32.
P = -16.6999 - 0.0101059 T + 0.00116512 T^2 + 0.173354 T V + 4.24267 V - 0.0684226 V^2
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