It is fairly easy to calculate the amount of CO2 produced...
A density drop of 1 point of density means approximately 2.13 g/L of sugar has fermented.
Approximately 47% of this fermented sugar is transformed into CO2, hence 1 gram of CO2 per liter of cider for each point of density drop.
Volumic mass of CO2 is 2 g/L under standard conditions (i.e. 20C), then this 1 g of CO2 is 500 mL, but this will vary with temperature.
Where it becomes more difficult is to evaluate the volume of one bubble. I would think this will vary from one airlock to another, and also depend on the amount of liquid in the airlock. Anyway, for the fun of it, let's assume 0.5 mL per bubble.
So let's calculate the production of CO2 per hour, taking FSU as density drop per 100 days, and V the volume of cider
Density drop in points per hour is FSU / (100 days x 24 hours per day) = FSU / 2400
Production of CO2 in mL per hour is (FSU x V x 500 mL) / 2400
So, let's say a carboy of 20 L, FSU of 50, this would produce 208 mL per hour, at .5 mL per bubble, approximately 400 bubbles per hour, or 7 per minute, or about 9 seconds per bubble. Would this make sense?