asUint vs U

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Martin Schoeberl

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Jan 19, 2022, 4:08:21 PMJan 19
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Hi all,

as I am working on an update of my Chisel book, I am wondering what is the (real) difference between .U an .asUInt. Following code shows that they are almost identical:

class UIntVsU extends Module {
val io = IO(new Bundle() {
val values = Output(Vec(5, UInt(3.W)))
})

val v = io.values

v(0) := 7.U
v(1) := 7.asUInt
val scalaInt = 7
v(2) := scalaInt.U
v(3) := scalaInt.asUInt
val signed = WireDefault(-1.S(3.W))
v(4) := signed.asUInt
}


Just the SInt (and probably Bundle and Vec) cannot be converted to an UInt with .U

Is there any best practice which one to use? .U is for sure less typing.

Cheers,
MArtin

Kevin Laeufer

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Jan 19, 2022, 4:09:51 PMJan 19
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I only use `.U` when I want to convert a Scala Int/BigInt to a Chisel UInt.

Kevin
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Richard Lin

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Jan 19, 2022, 4:27:12 PMJan 19
to chisel...@googlegroups.com, Kevin Laeufer
If I remember correctly, when these were first introduced, the idea was
to use .U for numeric literals (eg, 7.U) and .asUInt for variables (eg,
myScalaVariable.asUInt). I don't think there is a difference in
behavior, it's mostly a stylistic recommendation.
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