How to tell Cherrypy to use any available port?

[Sebastian Rahlf]

Hello!

This has been asked before but I could not find a satifying answer.

I want to use CherryPy in a test suite. It will always run on
localhost but I have no chance of knowing which ports will be
available beforehand as there may already be another instance started
by another test.

The way I went about this previously was to bind to ('127.0.0.1', 0)
which would guarantee an open port to be used. How would I do this
with CherryPy? Using module random, as previously suggested, is not an
option for me.

Thanks for any pointers!

Seb.

[Daniel Bryan]

Being a total cherrypy amateur I'm sure the community will have a much better suggestion than me, but perhaps during your server startup you could create simple socket connections, wrapped in a try/except, and iterate through a range of acceptable port numbers until you get one that's available (and which you have permission for)? Something like this..

import socket

def find_port(acceptable_ports):

port = acceptable_ports.pop()

while port in acceptable_ports:

serversocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)

try:

serversocket.bind((socket.gethostname(), port))

return port

except socket.error:

port = acceptable_ports.pop()

raise IOError('No available ports in your range sucked in')

port = find_port(range(1,80))

Goes without saying that this is ad hoc, ugly, probably breaks a whole bunch of import principles of network programming and good process behaviour. I'm sure there's some way to do this in a single line. 

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[Daniel Bryan]

Oh, my while loop there is fundamentally broken. Joy! This is what you get for answering list questions after months of no Python -___-