Oil lab

[Kelsey M]

Scientifically oriented question: What is the estimated size of an oil molecule?

Evidence : We used the formula 4/3(pi)*(r)^3. The diameter of the drop of oil was 0.5mm, and the radius would be 0.25mm. Using the formula 4/3(pi).25^3 we found out that the volume of the drop was .065mm^3. To find the area we used the formula (pi)(r)^2. The diameter for the spread of the oil molecule was 95mm, which means the radius was47.5mm. The thickness was calculated by using 0.065=(pi))2.5)^2h. We solved for h and got a thickness of 0.0033mm.

Explanation: We calculated the area of the spread oil drop using the formula A=(pi)(r)^2h and we ended with 3.69x10^-4mm which was also the size of an oil molecule.

Connection: A real life situation where we would use this is through nanotechnology. Using nanotechnology, things can made to be stronger or lighter.

Communication: The best way to communicate about nanotechnology is demonstrate what nanotechnology is, and how it effects our daily life. Also show what materials nanotechnology revolves around. This is to show how important nanotechnology.

Reflection: By comparing my results with other groups in the class I learned that most groups will get different answers. This is due to how precise or not each group was.