Unable to deserialize a json string - cereal::RapidJSONException

[Rajesh Khan]

This is my json string to an object

{ "connectionString" : "MyConnectionString", "value" :"MyVal" }

This is my class

struct Settings 

 {

   std::string connectionString;

   std::string value; 

   template<class Archive> 

   void serialize(Archive& ar) {

    ar(CEREAL_NVP(connectionString), CEREAL_NVP(value) ); 

    }

 };

And this is what I am doing:

std::ifstream ifs("Settings.json"); 

std::string content((std::istreambuf_iterator<char>(ifs)),(std::istreambuf_iterator<char>())); 

Settings settings; { 

  cereal::JSONInputArchive archive_in(ifs); 

  archive_in(settings); 

}

Any suggestion on what I might be doing wrong here ? The exception I get is at

document.h

 MemberIterator MemberEnd()              { CEREAL_RAPIDJSON_ASSERT(IsObject()); return MemberIterator(GetMembersPointer() + data_.o.size); }

Any suggestions on what I might be doing wrong ?

[Alessio Massaro]

If you construct an instance in code and serialize it, what does the json look like?

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[Avon Dalitz]

Hello! I believe that each parameter in "archive_in" needs to be identified as an object in JSON, like so

{
    "value0": {
        "connectionString": "",
        "value": ""
    }
}

[Rajesh Khan]

It looks like this

{

    "connectionString": "sdds",

    "val": "Mydevice"

[Rajesh Khan]

It looks like this

{

    "connectionString": "sdds",

    "value": "SomeValue"

}

On Monday, November 16, 2020 at 2:55:43 PM UTC-8 Alessio M wrote:

[Rajesh Khan]

@Avon thanks this works. Is there a way for me to not have to make it an object ? (i.e) not use value0 and have cereal deserialize the string i am using ?

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