python 2.5.2 and casperjs 1.0.0 : what is the minimum version of python to run casperjs

[Soufyan]

i everybody !

In production we got an debian lenny OS with python 2.5.2

when I run a casperjs command I got this error :

File "/srv/lib/casperjs/1.0.0-RC4/bin/casperjs", line 58
except OSError as err:
           ^
SyntaxError: invalid syntax

It is impossible for me to upgrade the OS.

any solutions please or ideas?

thanks,
best regards.

Soufyan

[Nicolas Perriault]

2012/11/12 Soufyan <amenzou...@gmail.com>:

> File "/srv/lib/casperjs/1.0.0-RC4/bin/casperjs", line 58
> except OSError as err:
> ^
> SyntaxError: invalid syntax

CasperJS executable requires Python >= 2.7

++

--
Nicolas Perriault
https://nicolas.perriault.net/
Phone: +33 (0) 660 92 08 67

[Soufyan]

Thank you for your response.

But maybe it will be interessant for you to know that on VM machine I got :


linux 2.6.32-5-amd64 kernel version

Python 2.6.6

phantomjs 1.7.0

casperjs 1.0.0-RC1

And all my scripts work fine

Why I don't know ;)

++

[Nicolas Perriault]

2012/11/13 Soufyan <amenzou...@gmail.com>:

> Python 2.6.6

> And all my scripts work fine

Oh right, that's because we removed the use of check_output() (2.7
only) to use execvp() instead (2.6 compatible) :)

[Soufyan]

Okay thanks for the precisions

good luck ++