Ignite my CRN Model with inlet temperature below auto ignition

[Deity Neo]

Hello Cantera Group,

I am currently working with CRN and try to generate a Model. https://cantera.org/examples/python/reactors/pfr.py.html 

My problem is that i have a temperature inlet boundary condition that is below the auto ingnition temperature. I tried to ignite the CRN with a Gaussian pulse like in https://cantera.org/examples/python/reactors/pfr.py.html but i found out that this will not work. Can you help me with my problem? 

Best Regards

Marian

[Deity Neo]

Edit: So I have no reaction in my CRN (no combustion). The goal is to simulate a RQL system.

[Steven DeCaluwe]

Hi Marian,

I have to confess that I do not know what the acronyms CRN and RQL mean.  Can you give me some more context?

Also, can you tell us why a Gaussian pulse does not work?  What happened when you tried it?

Best,

Steven

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[Deity Neo]

Hello Steven,

CRN: Chemical Reactor Network 

In this system i am using chain reactors to simulate the different combustor areas.

RQL: Rich Quench Lean is a combustor type

Actually it would be enough if the example is working with low inlet temperature conditions (with a combustion). The Gaussian pulse is not working because the the impulse needs time to travel trough the chain reactor.
At the end i still have the pulse in the system. 

I am using the kerosene at the moment, but it would also be fine if it is working with low temp. and h2 like in the example.

For a 0D approach with one reactor network and a lot reactors the Gaussian pulse is working.

Best Regards

Marian

[Deity Neo]

Still need help. Thank you.

[Steven DeCaluwe]

Hi Marian,

Do I understand correctly that you are sending a fuel pulse through, as in this example?

If you are below the autoignition temperature, I wonder if you might also need to add a temperature pulse?  How do the reactants ignite in the physical system you are modeling?  I remember seeing examples, previously, that used a Gaussian temperature pulse to simulate the impact of a spark ignition.

Best,

Steven

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