--
You received this message because you are subscribed to the Google Groups "Busy Beaver Discuss" group.
To unsubscribe from this group and stop receiving emails from it, send an email to busy-beaver-dis...@googlegroups.com.
To view this discussion on the web visit https://groups.google.com/d/msgid/busy-beaver-discuss/CADhnJ7BRGTd8oOiDwwNc2TeraZCCV9a9jOYpARJHDe6G_TKXYA%40mail.gmail.com.
1RB1RZ1LA2RB_1RC3RC1LA2LB_2LB2RC1LC3RB`
3^n <A 1^k 2^c 0^inf --> <A 1^k 2^x 0^inf for x = g_k^n(c)
g_1(y) = y + 2
g_{k+1}(y) = g_k^{y+1}(1)
0^inf A> 0^inf --(182)-->
0^inf 1 3^2 <A 1^13 2 0^inf -->
0^inf 1 <A 1^13 2^x 0^inf for x = g_{13}^2(1) --(1)-->
0^inf 1 Z> 1^13 2^x 0^inf
Score: g_13^2(1) + 14
I believe (but haven't checked carefully) that:
g_k(y) = 2{k-2}(y+3) - 3
g_k^x(1) = g_{k+1}(x-1) = 2{k-1}(x+2) - 3
so, Score = 2{12}4 + 11 > Ack(11)
(Where I am adopting the notation a{k}b
for $$a \uparrow^k b$$)
Permutations of 1RB1RZ1LA2RB_1RC3RC1LA2LB_2LB2RC1LC3RB
:
0^inf B> 0^inf --(84)--> 0^inf 1 3^2 <A 1^7 2 0^inf
0^inf C> 0^inf --(18)--> 0^inf 1 3^2 <A 1^1 2 0^inf
So these score g_7^2(1) + 8 = 2{6}4 + 5
and g_1^2(1) + 2 = 7
respectively.