Making Estimated Salt Solutions for CES, etc

[whoisbambam]

Can somebody help me with this answer?

Apparently CES and tDCS work better with saline-soaked sponge salt
soltions (as compared to water).

I want to make a crude 5% salt solution with distilled water and table
salt.

Morton Table salt contains 590mg per 1/4tsp

8 ounces of this water is about 240ml

how many teaspons of this table salt to make approximately 5%
solution? I am thinking the answer is about 1/2tsp:

1tsp/2360mg X 240ml/1 = 0.1016, or about 10.16%

I only want 5%, so use 1/2 tsp

????

Is there a better way to set this up so i can easily get the answer
based on the desired percent?

so, if i want a 3% solution, how many tsp, etc etc etc.

thanks.

[ao]

A quick search yielded this: http://educate-yourself.org/dc/saltwatersolutions.shtml

argumzio

[whoisbambam]

yeah, i saw that........i dont want to go buy sea salt.

and i dont want to make a liter of 100% saturated solution and
redilute cause it would take awhile.

so i was just lookng for a crude method to make variable solution
concentrations with distilled water and mortons table salt.

i dont need this for some chemistry class or anything, so it doesnt
have to be exact (after all, table salt contains chloride and other
stuff too)

just an approximation as i dont want to be WAY off on the estimation.

[Działo, Christopher]

Ha.

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[ao]

Okay, quick and dirty it is.

The standard procedure for simple saline solutions, then, is to take n
grams of solute (salt, or sodium chloride (NaCl)) for 100 mL of
solvent (water) to get the n% solution you want, that is, take mass(g)/
volume(mL)*100.

Note that the volume of solution should be 100mL *after* you've added
the solute, not before. Once you've made your solution, you can pour
it into a smaller container to yield the desired final amount you wish
to use.

There's all kinds of info on this stuff, so here's just one for more
which includes weight-in-weight solutions (practically equivalent as
1mL water = 1g water (specific gravity of H2O @ 4degC @ 1atm)):
http://www.ruf.rice.edu/~bioslabs/methods/solutions/formulas.html .

argumzio

[ao]

Oh, I forgot to add this, since you're using tablespoons and such.

Generally, a tablespoon of table salt is 17.06g, and there are 3
teaspoons in 1 tablespoon. So you'd want a little less than a teaspoon
(= 5.69g) to get 5g for your 5% saline solution.

http://convert-to.com/456/table-salt-amounts-converter.html

argumzio

[whoisbambam]

argumzio,

thank you for your help.

Yes, i was using teaspoon, which is why i said tsp

over here, tablespoon is something like Tbsp

Mortons table salt tells us how many milligrams of sodium is in their
product:
1/4 teaspon has 590mg of sodium.

So i shouldnt have to weight anything

this is why i set up that calculation the way i did. hopefully i was
in the ballpark as nobody has directly tried to review my solution
(pun)

[moe]

Here's another

g*100/(desired percent) = mass of final solution

g=grams of solute

For example to make a 5% solution out of the 1 tsp (2360 mg) of salt
listed in your first post:

(2.36 g salt)(100)/5 = 47.2 grams (or 44.84 ml water + 2.36 g salt in
this case)

[ao]

No problem.

You mean Morton's table salt contains 590mg of *sodium chloride* per
1/4 tsp, right? (Halite/salt is the molecule of the joined components
salt and chlorine which are toxic to humans on their own.)

Anyway, the calculation should be fairly straightforward:

590mg * 4 = 2.36g (1tsp) salt
multiply by 2
4.72g (2tsps)

Thus, you'll need a little over 2tsps of Morton's to be used as the
solute - four times the amount you calculated in the OP. But judging
from the impurities, you'll have to ignore the fact that it won't
strictly be a 5% solution, but 5% of it will be "salt".

2tsp = 11.38g total

4.72(salt)/11.38(total) = 41.5% of solute is salt

Given a rough approximation, 87% (= 1 - 11.38/[100-11.38]) of the
solution will be solvent, so it will be more like a 13% solution in
the final analysis.

Of course, since you probably don't have a precise measuring device to
obtain 100mL, you may want to use 4oz (118.3mL) as your goal;
therefore, the solute you'll need is:

118.3*.05 = 5.915g
divide by 41.5% = 14.25g which equals
2.5tsps

Thus, this result is 5 times larger than the one you had in the OP.
Make sure it's half of 8oz *after* mixing and you'll be set.

argumzio

[ao]

Sorry, I meant "sodium and chlorine" not salt... dumb slip.

argumzio

[whoisbambam]

argumzio,

Geesh.

Now you know why i ask questions.

thank you very, very, very much.

so i need 5 teaspoons for 8oz of water for a 'crude' 5% salt solution

way, way, way off i was...............

On May 3, 9:47 pm, ao <argum...@gmail.com> wrote: