> Hi all,
>
> I'm using header-only boost libs in two static libraries that will be linked
> into an executable.
>
> No boost components are used in the interfaces of those libs, boost is only
> used in the implementation inside the libraries.
>
> Is it possible to mix versions of boost in those two static libraries? Will
> the linker complain, or will it just get confused and mess up the
> executable?
In general, this is highly risky business. On GCC, each static library
will contain a copy of every template function used by a static library.
If the linker finds that the same function is used in both static libraries,
it will put only one copy in the output executable, and if the definitions
of those functions differ, you're in trouble. See the attached example, which,
then run, produces:
a.cpp:say
a.cpp:say
Which is clearly wrong. This *might* work with shared libraries, but you
need to consult your toolchain documentation.
There's nothing Boost can do to help here, except maybe changing namespace
name with each version.
- Volodya
For the past few years we've had a GCC option that allows you to expose
from dynamic libs only those names you specify, sort of like declspec on
Windows. I don't remember the name of the flag, though.
--
Dave Abrahams
BoostPro Computing
http://www.boostpro.com
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The only point to be careful about if 3d-party lib returns boost class
instances. These might be different in a newer version of the lib.
With Kind Regards,
Ovanes
> Vladimir Prus wrote:
>> dar...@gmail.com wrote:
>>
>>> Hi all,
>>>
>>> I'm using header-only boost libs in two static libraries that will be linked
>>> into an executable.
>>>
>>> No boost components are used in the interfaces of those libs, boost is only
>>> used in the implementation inside the libraries.
>>>
>>> Is it possible to mix versions of boost in those two static libraries? Will
>>> the linker complain, or will it just get confused and mess up the
>>> executable?
>>
>> In general, this is highly risky business. On GCC, each static library
>> will contain a copy of every template function used by a static library.
>> If the linker finds that the same function is used in both static libraries,
>> it will put only one copy in the output executable, and if the definitions
>> of those functions differ, you're in trouble. See the attached example, which,
>> then run, produces:
>>
>> a.cpp:say
>> a.cpp:say
>>
>> Which is clearly wrong. This *might* work with shared libraries, but you
>> need to consult your toolchain documentation.
>
> For the past few years we've had a GCC option that allows you to expose
> from dynamic libs only those names you specify, sort of like declspec on
> Windows. I don't remember the name of the flag, though.
-fvisibility, I believe. I actually though there's a way to cause a shared
library to prefer its own symbols -- but apparently it's not possible,
at least with gcc, in any easy way.
- Volodya
Version 1.34 might have a class A with one field of type int. Version
1.35 might add to the class an additional field. What hapen if 1.34
returns this type's instance to 1.35. And 1.35 will try to access the
additional field...
1.34:
struct A
{
int i;
};
1.35
struct A
{
int i;
double d;
};
A* get_A_from_134()
{
...
}
void modify_A_from_134_in_135()
{
get_A_from_134()->d=10.0; //You write to a memory which does not belong to A
}
This is what I mean. Can crash your soft... Best Thing would be in
this case to not return boost class instances over the lib boundaries
if you know that these rely on different versions.
Best Regards,
Ovanes