statementToCode

[Julian]

I am developing a generator in Blockly for a custom language. I am using the function Blockly.MyLanguage.statementToCode( block, 'TheNameOfInput' ). The problem is that I can only use this function for one block. However I want to get the code for every block in the input 'TheNameOfInput'. In what way can I access the next block (eventually every block) in the same input with the function statementToCode()? 

Kind regards,

 Julian

[Neil Fraser]

Generally each block will generate its own code, then call the generator on any next block.  Thus calling Blockly.MyLanguage.statementToCode( block, 'TheNameOfInput' ) will return the output of the entire stack, not just the one block at the top.

The mechanism for this is Blockly.Generator.prototype.blockToCode which calls the generator's scrub_ function (here's JavaScript's scrub_ as an example).  I'd recommend that your new generator have a scrub_ function that (recursively) appends the code for the next block onto the current code.

[Julian]

Hello Neil,

Thx for your time and the solution / example . Just like you suggested I didn't have a _scrub function after finding this out it worked. However I forgot to to share that I already solved it here. 

I found my solution on: https://blocklycodelabs.dev/codelabs/custom-generator/index.html?index=..%2F..index#8 

Kind regards,

Julian

Op maandag 27 september 2021 om 07:57:29 UTC+2 schreef neil....@gmail.com: