Find: (\d)|[(\d{2})]
Replace: \1\2\n (or just \1\2 if using "Extract")
Either \1 or \2 will be empty, so no harm in including both in the replacement.
On 29 Jul 2021, at 1:19, Tim A wrote:
How to not include the brackets as Howard asked? I figure it involves non-capture but it eludes me.