How much is a class C IP range worth?
Random Number
worth?
Anyone need one?
(not selling.... :-) just 'transferring usage' )
Inigua
are non transportable and the only way to transfer the IP is to connecting
to you (the owner).
I may be dead wrong though.
Freddy
Gregory Bond
> If I wanted to transfer 203.32.. Class C IP range to someone else what is it
> worth?
Nothing. You are not allowed to sell IP ranges. See www.aunic.net.
Random Number
time.
What's wrong with a very long lease?
Most ISP's charge for extra IPs... so a long lease on a whole subnet's gotta
be worth sumthing.
"Gregory Bond" <g...@itga.com.au> wrote in message
news:861yxfd...@hellcat.itga.com.au...
deadmeat
gotta
> be worth sumthing.
a class C is a whole network, not a subnet :)
Telstra Bigpond Direct give you upto a 64 IP subnet without questions, more
if you show you can use them. I suspect they will give you a whole Class C
for nothing provided you go for one of the more expensive plans like an ISP
would use. Without giving you IP's, they can't sell you the bandwidth so
it's in their best interests to give you what you need to use up more
bandwidth.
OTOH, end-luser services can charge extra for single IP's because they are
often not charged by the megabyte. They charge per-user (IP) instead.
Nick Andrew
>a class C is a whole network, not a subnet :)
A class C is a /24 (256 addresses) and it is a subnet of a /23
(512 addresses), a /22 (1024), a /21 (2048), and so on until we
get to /0 which is the whole IPV4 internet.
Nick.
--
Pacific Internet SP4 Fax: +61-2-9247-4738 Voice: 03-9674-7543
http://www.zeta.org.au/~nick/
"Sorry to say this, but the job falls to the ultimate defenders
of liberty - you and me." [Keith Henson, 2000-06-29]
Joan Colley
Would you like to try the maths again. There are only three classes - A B and C.
Surely class A is 256 and class B is 256 * 256 = 64K, so class C is 256 * 256 *
256 = 16M.
The whole IPV4 is 256 **4 = 4G - just enough for you and me.
Joan.
David Hill
"Joan Colley" <joan....@adc.com.au> wrote in message
news:39EEB88C...@adc.com.au...
> Nick,
>
> Would you like to try the maths again. There are only three classes - A B
and C.
>
> Surely class A is 256 and class B is 256 * 256 = 64K, so class C is 256 *
256 *
> 256 = 16M.
I thought it was the other way around... ie. Class A = 256^3 Class B = 256^2
and Class C = 256?
> The whole IPV4 is 256 **4 = 4G - just enough for you and me.
>
Dave.
Joan Colley
post.
Joan
Nick Andrew
>Would you like to try the maths again. There are only three classes - A B and C.
Wrong. There's also class D (and I think E) for special purposes.
>Surely class A is 256 and class B is 256 * 256 = 64K, so class C is 256 * 256 *
>256 = 16M.
I think you don't understand either my answer or the IPV4 address space. You should
go and read the relevant RFCs before posting incorrect contradictions.
"Class C network" is obsolete terminology. Today we call it a /24 subnet and it
contains 256 ip addresses. A /23 subnet contains 512 addresses, etc. etc.
You are trying to count the number of distinct instances of each class of network.
But you got it wrong.
There are not 256 class A networks - if there were 256 of them, where would we
fit the class Bs ?
From memory, old Class A networks came from 0.0.0.0 - 127.255.255.255
old Class B networks came from 128.0.0.0 - 191.255.255.255
old Class C networks came from 192.0.0.0 - 223.255.255.255
224.0.0.0 - 255.255.255.255 are used for special purposes, including special
addresses for multicasting (e.g. 224.0.0.9).
Matthew McDonald
>Wrong. There's also class D (and I think E) for special purposes.
That's correct, D and E. I think it's D for multicasting and E for
testing or I might have that reversed.
Regards
Matthew
--
____________________________________________________________
Matthew McDonald http://www.matthewmcdonald.com/
MobileWorld Phone Information http://www.mobileworld.org/
Brisbane, Australia_________________________________________
InMyTree
Class B is 65536 hosts
Class C is 256 hosts
Class D is Multicast mode
Class E is Reserved for future use
"Nick Andrew" <ni...@zeta.org.au> wrote in message
news:8smos0$kea$1...@gidora.zeta.org.au...
> Joan Colley <joan....@adc.com.au> writes:
>
> >Would you like to try the maths again. There are only three classes - A
B and C.
>
> Wrong. There's also class D (and I think E) for special purposes.
>
> >Surely class A is 256 and class B is 256 * 256 = 64K, so class C is 256 *
256 *
> >256 = 16M.
>
> I think you don't understand either my answer or the IPV4 address space.
You should
> go and read the relevant RFCs before posting incorrect contradictions.
>
> "Class C network" is obsolete terminology. Today we call it a /24 subnet
and it
> contains 256 ip addresses. A /23 subnet contains 512 addresses, etc. etc.
>
> You are trying to count the number of distinct instances of each class of
network.
> But you got it wrong.
>
> There are not 256 class A networks - if there were 256 of them, where
would we
> fit the class Bs ?
>
> From memory, old Class A networks came from 0.0.0.0 - 127.255.255.255
> old Class B networks came from 128.0.0.0 - 191.255.255.255
> old Class C networks came from 192.0.0.0 - 223.255.255.255
> 224.0.0.0 - 255.255.255.255 are used for special purposes, including
special
> addresses for multicasting (e.g. 224.0.0.9).
>