I'm seeing an "extraneous input" error with input "\aa a" and the following grammar:
Cool.g4
grammar Cool;
import Lex;
expr
: STR_CONST # str_const
;
Lex.g4
lexer grammar Lex;
@lexer::members {
public static boolean initial = true;
public static boolean inString = false;
public static boolean inStringEscape = false;
}
BEGINSTRING: '"' {initial}? {
inString = true;
initial = false;
System.out.println("Entering string");
} -> more;
INSTRINGSTARTESCAPE: '\\' {inString && !inStringEscape}? {
inStringEscape = true;
System.out.println("The next character will be escaped!");
} -> more;
INSTRINGAFTERESCAPE: ~[\n] {inString && inStringEscape}? {
inStringEscape = false;
System.out.println("Escaped a character.");
} -> more;
INSTRINGOTHER: (~[\n\\"])+ {inString && !inStringEscape}? {
System.out.println("Consumed some other characters in the string!");
} -> more;
STR_CONST: '"' {inString && !inStringEscape}? {
inString = false;
initial = true;
System.out.println("Exiting string");
};
WS : [ \t\r\n]+ -> skip ; // skip spaces, tabs, newlines
ID: [a-z][_A-Za-z0-9]*;
Here's the output:
$ grun Cool expr -tree
"\aa a"
Entering string
The next character will be escaped!
Escaped a character.
Consumed some other characters in the string!
Exiting string
line 1:0 extraneous input '"\aa' expecting STR_CONST
(expr "\aa a")
Interestingly, if I remove the ID rule, antlr parses the input fine. Here's the output when I remove the ID rule:
$ grun Cool expr -tree
"\aa a"
Entering string
The next character will be escaped!
Escaped a character.
Consumed some other characters in the string!
Exiting string
(expr "\aa a")
Any idea what might be going on? Why does antlr throw an error when ID is one of the Lexer rules? I realize that this may not be the best way to parse strings with escape sequences, but I'm still curious why antlr throws an error. Is this expected behavior in antlr?
Thanks,
Jorge