STG grammar

[Andrzej Borucki]

I search .stg files grammar, it is simple, but for example how to use "<" in template?

[Andrzej Borucki]

I found: https://theantlrguy.atlassian.net/wiki/display/ST4/Group+file+syntax

[Andrzej Borucki]

I am beginner using StringTemplate. 

I use method: 

public static void twoST() {

String result;

STGroup group = new STGroupDir(".");

ST st = group.getInstanceOf("decl"); 

st.add("type", "int");

st.add("name", "x");

st.add("value", 0);

result = st.render(); // yields "int x = 0;"

System.out.println(result);

}..

with decl.st : decl(type, name, value) ::= "<type> <name><if(value)>;"

init.st : init(v) ::= "<if(v)> = <v><endif>"

. 1:54: premature EOF

whereas if I use 

public static void testSTG() {

STGroup group = new STGroupFile("test.stg");

ST st = group.getInstanceOf("decl");

st.add("type", "int");

st.add("name", "x");

st.add("value", 0);

String result = st.render(); // yields "int x = 0;"

System.out.println(result);

}

with test.stg :

decl(type, name, value) ::= "<type> <name><init(value)>;"

init(v) ::= "<if(v)> = <v><endif>"

Is OK :

int x = 0;

but in test.stg I add

 if(v) ::= "if <v>"

then is again 

int x = 0;

instead 

int x if(0)= 0;

[Sam Harwell]

In your first decl.st, you have an <if(value)> that does not have a matching <endif> tag.

 

Other than that, I’m not sure what your question is.

 

Sam

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[Andrzej Borucki]

Yes, in first should be "init", not "if"