win_shell command execution

[Uppara venkat]

Hi all,

I'm trying to list the files with the name of  "PackageDeploy" using as below but getting all other files also in the directory.

- win_shell: 'dir PackageDeploy*.* /b {{directory}}\configurations\jmxterm > {{directory}}\configurations\temp'
      args:
         executable: cmd
      register: list_out

Could you please suggest the right method for list the file with name ?

Best regards,

Venkat

[J Hawkesworth]

You would probably need to write like this:

- win_shell: 'dir PackageDeploy*.* /b > {{directory}}\configurations\temp'

   args:
      executable: cmd

      chdir: '{{directory}}\configurations\jmxterm'     

   register: list_out

But its probably much better to use win_find module https://docs.ansible.com/ansible/latest/modules/win_find_module.htmld as the results will be easier to make use of than the contents of your list_out registered variable.

- name: find PackageDeploy files

  win_find:

     paths: '{{directory}}\configurations\jmxterm'

     patterns: 'PackageDeploy*.*'

  register: package_deploy_info

Hope this helps,

Jon

[Uppara venkat]

Thanks Jon, it's working now

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Thanks& Regards,
venkatesulu.U
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