How to execute Play 2 only if Play 1 succeeds
Shifa Shaikh
I have two Plays having one task each.
The first Play 1 checks if the/var/test.datexists on each target host.
Only if the Play 1 is successful do I want the second play Play 2 to run which executes scripts in parallel.
If Play 1 fails i.e if the test.dat does not exist I wish to terminate the entire playbook without the Play 2 getting executed.
For this purpose, I have set any_errors_fatal set to true
I need to have an ansible Play strategy set to free as each of the scripts takes 30 minutes to complete hence running them in parallel is the requirement.
My understanding of ansible is limited.
I understand that if I have both the tasks under a single Play and set the strategy to free both the tasks will run in parallel which is something I do not want.
---
- name: Play 1- check for login and script
hosts: all_hosts
any_errors_fatal: true
strategy: free
tasks:
- name: Check script existence
shell: "ls /var/test.dat"
register: checkscript
- name:
fail:
msg: "script {{ scriptdet }} missing on {{ inventory_hostname }}"
when: checkscript.rc != 0
- name: Play 2- Run scripts
hosts: all_hosts
user: "{{ USER }}"
strategy: free
tasks:
- name: Execute backup script
shell: "{{ scriptdet }}"
args:
chdir: ~/..I tried the above playbook but I see the second play executes despite the first play's task failed.
Can you please suggest how can I get this to work?
Dick Visser
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